The solubility of silver bromide in hypo solution is due to the formation of :

$5.33 \text{ g}$ of $CrCl_3 \cdot 6H_2O$,which is a $1:3$ electrolyte,is dissolved in water and passed through a cation exchanger. The chloride ions in the eluted solution,on treatment with $AgNO_3$,result in $8.61 \text{ g}$ of $AgCl$. The ratio of moles of complex reacted and moles of $AgCl$ formed is . . . . . . $\times 10^{-2}$. (Nearest integer) [Molar mass in $\text{g mol}^{-1}$: $Cr = 52, Ag = 108, Cl = 35.5, H = 1, O = 16$]

Arrange the following complexes in the increasing order of conductivity of their solution:
$[Co(NH_{3})_{3}Cl_{3}], [Co(NH_{3})_{4}Cl_{2}]Cl, [Co(NH_{3})_{6}]Cl_{3}, [Cr(NH_{3})_{5}Cl]Cl_{2}$

$AgCl$ precipitate dissolves in ammonia due to the formation of

Aqueous copper sulphate solution (blue in colour) gives:
$(i)$ a green precipitate with aqueous potassium fluoride,and
$(ii)$ a bright green solution with aqueous potassium chloride
Explain these experimental results.

$[Cu(CN)_4]^{2-}$ is colourless as it absorbs light in